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10x^2-98x+70=0
a = 10; b = -98; c = +70;
Δ = b2-4ac
Δ = -982-4·10·70
Δ = 6804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6804}=\sqrt{324*21}=\sqrt{324}*\sqrt{21}=18\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-18\sqrt{21}}{2*10}=\frac{98-18\sqrt{21}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+18\sqrt{21}}{2*10}=\frac{98+18\sqrt{21}}{20} $
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